A hot stell ball of mass 1 kg is dropped into a 4 L bucket of water at room temperature (70 degrees F). If the system reaches an equilibrium temperature of 320 K, what was the initial temperature of the steel ball before it was dropped into the water? Cp of steel = 490 J/kg degrees C, Cp of water = 4186 J/kg degrees C.

Answer 1

the sum of heats gained is zero.

HeatgainedSteelBall+ HeatgainedWater=0
1kg*490*(Tf-Ti)+4000*4186*(Tf-70)=0
solve for Ti

Answer 2

thank you!