A hot-air balloonist, rising vertically with a constant speed of 5.00 m/s releases a sandbag at the instant the balloon is 40.0 m above the ground. After it is released, the sandbag encounters no appreciable air drag. Compute the position of the sandbag at 0.250 s after its release.

Answer 1

h = [1/2 * (-9.81 m/s^2) * (0.250 s)^2] + (.250 s * 5.00 m/s) + 40.0 m