Asked by karim
A hot-air balloon of mass 200 kg is descending vertically with downward acceleration of magnitude 1.2 m/s2. How much mass (ballast) must be thrown out to give the balloon an upward acceleration of magnitude 1.2 m/s2 (same magnitude but opposite direction)? Assume that the upward force from the air (the lift) does not change because of the decrease in mass.
Answers
Answered by
drwls
Let B = the buoyancy force and M = the initial total mass. Let m be the ballast mass released
M g - B = M*1.2 m/s^2
(M-m)g -B = -M*1.2 m/s^2
Solve for m.
m g = M*2.4m/s^2
m/M = 2.4/g
m = 0.245 M = 49 kg
M g - B = M*1.2 m/s^2
(M-m)g -B = -M*1.2 m/s^2
Solve for m.
m g = M*2.4m/s^2
m/M = 2.4/g
m = 0.245 M = 49 kg
Answered by
Mr.Hojman
Please don't cheat and use this website do your work and learn! - spread this message!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.