A hot-air balloon is rising upward with a constant speed of 2.20 m/s. When the balloon is 2.50 m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground?

Answer 1

Vi = 2.2
initial height = 2.5

h = 2.5 + 2.2 t - 4.9 t^2 = 0 when hits ground

4.9 t^2 - 2.2 t - 2.5 = 0

t = [ 2.2 +/-sqrt (4.84 + 22) ] / 9.8

t = [ 2.2 + 5.18 ]/ 9.8 (ignore - time)
t = .753 seconds