Asked by Jerry
A hot-air balloon is rising straight up with a speed of 5 m/s. A ballast bag is released from rest relative to the balloon when it is 8.2 m above the ground. How much time elapses before the ballast bag hits the ground?
I don't get what equations or what values to use for this equation. can anyone help me?
I don't get what equations or what values to use for this equation. can anyone help me?
Answers
Answered by
bobpursley
Intial height, initial velocity given, looking for time.
h=Ho +Vi*t-1/2 9.8 t^2
solve when h=0. You know Ho, Vi.
Notice it is a quadratic.
h=Ho +Vi*t-1/2 9.8 t^2
solve when h=0. You know Ho, Vi.
Notice it is a quadratic.
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