101kPa is atmospheric pressure.
6000 is in meters, of little use here. I don't know why you did that.
A hot air balloon is hovering at an altitude of 6000 meters. The pilot decides that it is time to descend and turns off the balloon's burners. Once the balloon reaches the ground, the gas inside the balloon occupies 980 m^3 and is at atmospheric pressure. If the pressure of the gas inside of the balloon was 75,000 Pascals at its highest altitude, what was the volume of the gas at that time?
Physics - bobpursley, Saturday, February 18, 2012 at 6:21pm
Assuming temp is constant?
75kPa*V=101kPa*980
solve for V
Where did you get the 101kpa.
I am getting v2=p1v1/p2
(6000)(980m^3) divided by 75000 = 78.4 m^3
1 answer
1 answer