To determine how many training sessions the horse trainer can conduct with the bag of 42 mints, where each session requires 5 treats, we can set up the following equation:
Let \( x \) be the number of training sessions. Since each session requires 5 mints, the total number of mints used for \( x \) sessions is \( 5x \).
The equation based on the total number of mints in the bag, which is 42, is:
\[ 5x \leq 42 \]
To find the maximum number of complete training sessions, we can solve for \( x \):
\[ x \leq \frac{42}{5} \] \[ x \leq 8.4 \]
Since the number of training sessions must be a whole number, we take the largest whole number less than or equal to 8.4, which is 8.
Thus, the trainer can conduct a maximum of 8 training sessions with the 42 mints, and the equation that represents this scenario is:
\[ 5x \leq 42 \]
The viable solutions for \( x \) (the number of sessions) will be \( 0, 1, 2, 3, 4, 5, 6, 7, 8 \).