A horse trainer has a bag of pink sugar mints for horse treats. She needs five treats per training session. The bag holds 42 mints. Which equation shows the number of horses that she can train and is a solution a viable option?(1 point)

Question

Responses

h−5=42 and h=47, which is not viable.
h minus 5 equals 42 and h equals 47 , which is not viable.

5h=42, so h=8.4 horses, which is not viable.
5 h equals 42 , so h equals 8.4 horses, which is not viable.

5h=42, so h=8.4 horses, which is viable.
5 h equals 42 , so h equals 8.4 horses, which is viable.

h5=42 and h=210, which is not viable.

Answer 1

To determine the number of horses the trainer can train, we start with the information given. The trainer needs 5 treats per training session, and the bag holds 42 mints.

We can set up the equation as follows:

\( 5h = 42 \)

Where \( h \) is the number of horses. To solve for \( h \):

\[ h = \frac{42}{5} = 8.4 \]

Since it is not possible to train a fraction of a horse, the number of horses that can be trained must be a whole number. Thus, 8.4 horses is not viable.

Now let's analyze the options based on the expressions given:

1. h − 5 = 42 and h = 47, which is not viable.
2. 5h = 42, so h = 8.4 horses, which is not viable.
3. 5h = 42, so h = 8.4 horses, which is viable. (This is incorrect because 8.4 is not a whole number.)
4. h5 = 42 and h = 210, which is not viable. (This seems to be a typographical error.)

The correct assessment from the options would be:

5h = 42, so h = 8.4 horses, which is not viable.

This accurately reflects the situation: the horse trainer can train a maximum of 8 horses and has some mints left over since 5 x 8 = 40 mints. She cannot train 9 horses because that would require 45 mints, which exceeds the 42 mints in the bag.