A horse runs off of a 11 meter high cliff into the sea. The horse is running at a speed of 3.6 m/s. How much time does the horse spend in the air? How far from the base of the cliff is the horse when it hits the water?

Answer 1

Time in the air is given by:
(1/2) g T^2 = 11 m

V * T = horizontal distance traveled

Answer 2

First, how long in the air?

h=1/2 g t^2 solve for t.

How far away horizontally?

d=rt
d=3.6m/s * time