h = 0.5g*t^2 = 0.031 m
4.9t^2 = 0.031
t^2 = 0.00633
Tf = 0.0795 s. = Fall time.
Dx = Xo*Tf = 720 m/s * 0.0795s = 57.3 m.
A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 720 m/s. The barrel is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.031 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?
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