A horizontal force of 200 N is applied to a 55 kg cart across a 10 m level surface. If the cart accelerates at 2 m/s^2 then what is the work done by the force of friction as it acts to the motion of the cart? Hint calculate the force of friction using newtons second law.

Question

the answer is -900J...but how do i get that?

Answer 1

There are a couple of ways to do this.

Netforce= ma
200N+friction=ma
-200N + ma=friction solve for friction force.
Work done on by friction=forcefricion(10m)
Now notice

Answer 2

thanks

Answer 3

The answer is 900j, since w=fd, we first calculate the net force f=ma=110N then net force - 200N = 90.
Hence: w= (90) (10) = 900j

Answer 4

Yes