Wc = m*g = 32.5kg * 9.8N/kg = 318.5 N.=
Wt. of crate.
Fc = 318.5N [0o]
Fp = 318.5*sin(0) = 0 = Force parallel to surface.
Fv = 318.5*cos(0) = 318.5 N. = Force perpendicular to surface.
a. Work = F*d = 150 * 4.95 = 742.5 Joules.
b. Fap-u*Fv = m*a
150-Fp-u*Fv = m*a
150-0-318.5u = m*a = m*0 = 0
318.5u = 150
u = 0.470.
A horizontal force of 150 N is used to push a 32.5-kg packing crate a distance of 4.95 m on a rough horizontal surface. If the crate moves at constant speed, find each of the following.
(a) the work done by the 150-N force?
(b) the coefficient of kinetic friction between the crate and the surface ?
1 answer
1 answer