A horizontal force F is exerted on a 20-kg box to slide it up a 30 degrees incline. The friction force retarding the motion is 80 N.How large must F be if the acceleration of the moving box is to (a)zero and (b) 0.75m/s2?

Answer 1

weight force down slope = m g sin 30
= .5 m g

F force up slope = F cos 30 = .866 F

friction fore down slope = 80

total force up slope = .866 F -.5mg -80
= m a

Answer 2

Phy

Answer 3

Next step of queßtion

Answer 4

(a) 206 N
(b) 233 N