A horizontal 791 N merry-go-round is a solid disk of radius 1.48 m, started from rest by a constant horizontal force of 50.0 N applied tangentially to the edge of the disk. Find the kinetic energy of the disk after 3.01 s.

I am having trouble on which formula to exactly use for this problem. i no KE=.5mv^2 but how would it translate to this problem.

2 answers

KineticEnergy=1/2 I* w^2
find w from
Torque=I*alpha
force*radius=I * alpha

w=alpha*time
so t clarify W can be found through alpha times time?

also, what does I stand for?