x = 1.40 t^2 - .0505 t^3
at t = 0, x = 0
at t = 1.91, x =1.40 * 1.91^2 - .0505 * 1.91^3 = 4.755 meters
so
4.755 meters in 1.91 seconds = 2.5 m/s
do the others the same way, find out how far it went in the time interval and divide by the time interval
A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the equation x(t)= α t2− β t3, where α = 1.40m/s2 and β = 5.05×10−2m/s3
A) What is the average velocity of the car for the time interval t=0 to t1=1.91s?
B) What is the average velocity of the car for the time interval t=0 to t2 = 3.99s?
C) Calculate the average velocity of the car for the time interval t1 = 1.91s to t2 = 3.99s
I don't know where to even start.
3 answers
Can you help me get started on C? I'm stuck there.
Two insulating spheres have radii 0.300 cm and 0.500 cm, masses 0.500 kg and 0.700 kg, and uniformly distributed charges of -2.00 µC and 3.50 µC. They are released from rest when their centers are separated by 1.00 m.
(a) How fast will each be moving when they collide? (Hint: Consider conservation of energy and of linear momentum.
(a) How fast will each be moving when they collide? (Hint: Consider conservation of energy and of linear momentum.
2 answers