the max A lies on the axis of symmetry
Wmax = -b / 2a = -200 / (2 * -2) = 50
A homeowner wants to enclose a rectangular piece of land beside a river. He must put a fence on 3 sides of the field (the river forms the fourth side). The field has length L (which runs parallel to the river) and width W. The homeowner has 200 yards of fencing material. What should the length of the field L and the width of the field W be in order to produce the maximum possible area using all 200 yards of fence?
So I know that A=WL, and that 2W+L=200
I changed L to 200-2W, then got
A=W(200-2W)=200W-2W^2
But i'm not sure what to do next, I've been searching and would be really grateful if someone can help, thanks!
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