Translational KE is (1/2) M V^2
Rotational KE is (1/2)I w^2
= (1/2) M R^2*(V/R)^2 = (1/2) M V^2
Your answer is correct but your reasoning is faulty. The ratio could be anything and they would still add up to give total KE
A hollow tube (I = MR2) rolls without slipping along the surface. The ratio of its translational kinetic energy to its rotational kinetic energy is
a. 1
b. 2
c. 3
d. 1/2
e. 1/3
I say A becasue both add up to get the total kinetic energy.
2 answers
The Answer is "I don't know. Ask I".
1 answer