To find the volume of a square pyramid, we can use the formula:
\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
For a square pyramid with a base side length of \( s \) and a height \( h \):
- Base Area \( = s^2 \)
- Height \( h = 2.75 \) in.
Given that the base is a square with side length of \( s = 2.75 \) in., we calculate the base area:
\[ \text{Base Area} = (2.75)^2 = 7.5625 , \text{in}^2 \]
Now we can substitute the values into the volume formula:
\[ V = \frac{1}{3} \times 7.5625 , \text{in}^2 \times 2.75 , \text{in} \]
Now perform the multiplication:
\[ V = \frac{1}{3} \times 20.816875 , \text{in}^3 \]
Calculating the final volume:
\[ V = \frac{20.816875}{3} \approx 6.93895833 , \text{in}^3 \]
Rounding this to the nearest hundredth gives:
\[ V \approx 6.94 , \text{in}^3 \]
Thus, among the choices given, the approximate volume of the ornament is:
6.93 in.³