A hockey puck with a mass of 0.18 kg at a velocity of 40 m/s toward a goal keeper. The goalkeeper has a mass of 120 kg and is at rest. Assuming a closed system find the total momentum of the puck before the puck is caught by the goalkeeper

Answer 1

The momentum of an object is given by the product of its mass and velocity.

The momentum of the hockey puck can be calculated using the equation:

Momentum (puck) = mass (puck) × velocity (puck)

Given that the mass of the puck is 0.18 kg and its velocity is 40 m/s, we can substitute these values into the equation to find the momentum of the puck:

Momentum (puck) = 0.18 kg × 40 m/s = 7.2 kg⋅m/s

Since momentum is a vector quantity (it has both magnitude and direction), we should specify the direction for consistency.

The total momentum of the puck before it is caught by the goalkeeper is 7.2 kg⋅m/s, in the direction of motion of the puck.