A hockey puck moving at 28 m/s is caught by an 80.00 kg man who was at rest. The man and the puck move together after the collision. The pucks mass is 0.16 kg. What is the final velocity?

1 answer

m1 = 0.16 kg
m2 = 80kg
V1 = 28 m/s.

(m1+m2)*V = m1*V1
(0.16+80)V = 0.16*28
V = 4.48/(0.16+80) = 0.056 m/s.