a. a = (Vf - Vo) / t,
a = (6.1 - 10.6) / 5 = -0.9m/s^2.
c. d = (Vf^2 - Vo^2) / 2a,
d = ((6.1)^2 - (10.6)^2) / -1.8 = 41.8m.
A hockey puck is hit on a frozen lake and starts moving with a speed of 10.6 m/s. Five seconds later, its speed is 6.10 m/s.
(a) What is its average acceleration?
m/s2
(b) What is the average value of the coefficient of kinetic friction between puck and ice?
(c) How far does the puck travel during this 5.00 s interval?
m
1 answer
1 answer