Fk = u*Fn = 0.08*9.8M = 0.784M.
-0.784M = M*a.
a = -0.784 m/s^2.
V^2 = Vo^2 + 2a*d.
0 = 6.7^2 - 2*0.784d,
1.568d = 44.89,
d = 28.6 m.
A hockey puck is given an initial speed of 6.7 m/s. If the coefficient of kinetic friction between the puck and the ice is 0.08, how far (in m) does the puck slide before coming to rest?
1 answer