A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 14 m/s, skates by with the puck. After 3.5 s, the first player makes up his mind to chase his opponent.

(a) If he accelerates uniformly at 4.0 m/s2, how long does it take him to catch his opponent? (Assume the player with the puck remains in motion at constant speed.)
s
(b) How far has he traveled in this time?
m

2 answers

d1 = V1*t = 14m/s * 3.5s. = 49 m. Head-start.

a. d2 = 49 + V1*t.
0.5a*t^2 = 49 + V1*t.
0.5*4*t^2 = 49 + 14*t.
2t^2-14t-49 = 0.
Use Quadratic Formula.
t = 9.56 s.

b. d = 0.5a*t^2.
For this question t^2+ (what s)t+ what s^2=0
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