a hit air ballon rises vertically upwards with an acceleration of 1 m/s .ten seconds after the ballon is made to rise from the ground ,a ball is released from the balloon. the maximum height reached by the ball is

Answer 1

you need altitude at release, velocity at release, then solve.
altitude at release:
h=1/2 a t^2=1/2*1*10^2=50meters
v=a*t=1*10=10m/s

The ball total energy at release: 1/2 m v^2 + m*g*h
Total energy= m (10^2/2 + 9.8*50)
now at max height, energy is all PE, so
mg*MAXHEIGHt=m (10^2/2 + 9.8*50)
9.8*maxheight= (10^2/2 + 9.8*50)
and you solve for maxheight.