a high school wrestling mat must be square with 38-foot sides and contain two circles as shown. suppose the inner circle has a radius of "s" feet and the outer circle's radius is nine feet longer than the inner circle.

Question

*write an expression for the area of the larger circle.

* write an expression for the area of the suqare outside the circle.

*use the expression to find the area if s=1.

Answer 1

The outer circle has radius s + 9. Its area is pi(s+9)^2, and the area outside the outer circle is (38)^2 - pi(s+9)^2

Answer 2

Does anyone know the answers for this one?

The radius of a circle is 98 mm. What is the area of the circle? Write your answer to the hundredths place. Use 3.14 for π.

Answer 3

The area of the circle is given by the formula A = πr^2, where r is the radius of the circle.

Substituting the given values, we get:

A = 3.14 x (98)^2
A = 30171.52

Rounding to two decimal places, the area of the circle is 30171.52 mm^2.

Answer 4

How come I get different answers?

Answer 5

It's possible that you made a mistake in your calculations or used a different value for pi.

Using the correct value of pi, the area of the circle with radius 98 mm should be:

A = πr^2
A = 3.14 x (98)^2
A = 30171.52 mm^2

If you used a different value for pi, your answer would be different. For example, if you used 3.14159 for pi, your answer would be:

A = πr^2
A = 3.14159 x (98)^2
A = 30194.03 mm^2

However, since the question specifies to use 3.14 for pi, you should use that value to get the correct answer.