A high-jumper clears the bar and has a downward velocity of -6.00 m/s just before landing on an air mattress. The mass of the high-jumper is 53.7 kg. What is the magnitude and direction of the impulse that the air mattress exerts on her? Assume that upward is the positive direction.

Answer 1

impulse=change of momentum
impulse=mass(final velocity-intial velocity)
= 53.7(6) kg m/s