Asked by Cal

A helium nucleus (charge = 2e, mass = 6.63 10-27 kg) traveling at a speed of 6.20 105 m/s enters an electric field, traveling from point circle a, at a potential of 1.50 103 V, to point circle b, at 4.00 103 V. What is its speed at point circle b?
Answered by drwls
Kinetic energy increase = (potential increase) * charge

Use the final K.E and helium nucleus mass to get the velcoity
Answered by Haya
A helium nucleus ( charge2e mass
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