A helium nucleus (charge = 2e, mass = 6.63 10-27 kg) traveling at a speed of 6.20 105 m/s enters an electric field, traveling from point circle a, at a potential of 1.50 103 V, to point circle b, at 4.00 103 V. What is its speed at point circle b?

Question

A helium nucleus (charge = 2e, mass = 6.63  10-27 kg) traveling at a speed of 6.20  105 m/s enters an electric field, traveling from point circle a, at a potential of 1.50  103 V, to point circle b, at 4.00  103 V. What is its speed at point circle b?

drwls · Answer

Kinetic energy increase = (potential increase) * charge Use the final K.E and helium nucleus mass to get the velcoity

Haya · Answer

A helium nucleus ( charge2e mass