A helicopter scoops a load of water out of a lake, to dump on a forest fire. The helicopter exerts 6480N of force on the water while rising high enough to fly over a mountain. If the helicopter does 1.62×10^6 J of work on the water while lifting it, how high does it lift the water?

1 answer

To find the height the helicopter lifts the water, we can use the work-energy principle:

Work done on the water = Change in potential energy of the water

Given:
Force exerted by the helicopter (F) = 6480N
Work done on the water = 1.62×10^6 J

Work done = Force x Distance
1.62×10^6 J = 6480N x Distance
Distance = 1.62×10^6 J / 6480N
Distance = 250 meters

Therefore, the helicopter lifts the water to a height of 250 meters.