A helicopter of mass M is carrying a box of mass m at the end of a rope and is moving horizontally with constant acceleration 'a'. the acceleration due to gravity is 'g'. neglect air resistance. the rope is stretched out from the helicopter at a constant angle 'theta' to the vertical. what is the angle?
1 answer
i am getting the answer tan'theta' = ma/Mg but the answer is tan'theta'= a/g
0 answers