If release occurs at t=0, the vertical height ot the package after that, in meters, is
y = 125 + 5.2 t -4.9 t^2
(The 4.9 is g/2, and g is the acceleration of gravity in units of m/s^2)
Solve the equation y = 0 and you will get the time that it his the ground. It is a quadratic equation with two roots. Take the positive one.
t = [-5.2 -sqrt(5.2^2 +4*125*4.9)]/(-9.8)
= 5.61 seconds
A helicopter is ascending vertically with a speed of 5.20 m/s. AT the height of 125m above the earth, a package is dropped from a window.How much time does it take for the package to reach the ground.
****Note: Please show the steps.
4 answers
thank you so much!
You a Real One
A helicopter is ascending vertically with a speed of 5.10 m/s. At a height of 105 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground? [Hint: v0 for the package equals the speed of the helicopter.
Note: Please show the steps.
Note: Please show the steps.
1 answer