A helicopter flies 65km [N32°E] then 42km[E 21°] determine the total displacement of the helicopter.
3 answers
my answer
I agree. I used the law of cosines.
All angles are measured CCW from +x-axis.
Disp. = 65km[58o] + 42km[21o].
(65*Cos58+65*sin58) + (42*Cos21+42*sin21 =
(34.44+55.12i) + (39.21+15.05i) =
73.65 + 70.17i = 101.7km[43.6o].
Disp. = 65km[58o] + 42km[21o].
(65*Cos58+65*sin58) + (42*Cos21+42*sin21 =
(34.44+55.12i) + (39.21+15.05i) =
73.65 + 70.17i = 101.7km[43.6o].
1 answer