A helicopter descends from a height of 600 m with uniform negative acceleration, reaching the ground at rest in 5.00 minutes. Determine the acceleration of the helicopter and its initial velocity.

Question

bobpursley · Accepted Answer

Assuming it is uniform motion,then
Vf^2=Vi^2+2ad
a=-Vi^2/1200

and
vf=vi+at
0=Vi-Vi^2/1200 *5*60

0=Vi(1-Vi/300)

Vi=300m/s
a=..
check my work.
Notice Vi is positive, it was going up at a rapid rate, if these calcs are correct.

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myth · Answer

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