volume of ball = (4/3)π(4.5)^3
So that is the change in volume in the cylinder once removed
π(6^2) h = (4/3)π(9/2)^3
36h = (4/3)(729/8) = 243/2
h = 243/72 = 27/8
the water will fall 27/8 cm or 3.375 cm
check my arithmetic.
A heavy 9cm diameter ball is placed in an empty cylindrical tin
of diameter 12cm. Enough water is poured into the can to cover
the ball.if the ball is then removed , how far does the water
level fall
1 answer