A heating coil of power 500W boils a certain quantity of water (at boiling point) in 25 minutes What is the amount of water present ( specific heat capacity of vaporization of water is 33600J/kg/k

Answer 1

To calculate the amount of water present, we can use the equation:

Power = Energy / Time

First, let's convert the time from minutes to seconds:

25 minutes = 25 * 60 = 1500 seconds

Now, we can rearrange the equation to solve for energy:

Energy = Power * Time

Energy = 500W * 1500s = 750,000 J

The energy required to boil the water is equal to the mass of water multiplied by the specific heat capacity of vaporization of water:

Energy = Mass * Specific heat capacity

750,000 J = Mass * 33,600 J/kg

Now we can solve for the mass of water:

Mass = 750,000 J / (33,600 J/kg) = 22.3214 kg

Therefore, the amount of water present is approximately 22.32 kg.