a heater wire length 50cm and a 1mm^2 in cross section carries a current of 2A when connected across a 2 V battery. what is the resistivity of the wire?
2 answers
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Given:
L = 50 cm = 0.50 m.
A = 1mm^2 = 10^-6 m^2.
E = 2 Volts.
I = 2 Amps.
R = E/I = 2/2 = 1 Ohm.
R = p*L/A.
1 = p*0.5/10^-6,
p = 2*10^-6 Ohm-meters = Resistivity.
L = 50 cm = 0.50 m.
A = 1mm^2 = 10^-6 m^2.
E = 2 Volts.
I = 2 Amps.
R = E/I = 2/2 = 1 Ohm.
R = p*L/A.
1 = p*0.5/10^-6,
p = 2*10^-6 Ohm-meters = Resistivity.
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