A heat pump releases 103.0 kcal as it removes 54.0 kcal at the evaporator coils. How much work does this heat pump ideally accomplish? The answer should be in KJ

Answer 1

I see this problem this way. Perhaps another tutor will look at it too.
dE = q+w
-103 = q + w
If the evaporator coils lose 54 kcal that is -54 from the coils(exothermic at the coils) which makes it + 54 kcal to the heat pump.
Then -103 = 54 + w
w = ?