A heat pump has a coefficient of performance of 4.5. If the heat pump absorbs 46.1 cal of heat from the cold outdoors in each cycle, what is the amount of heat expelled to the warm indoors?

Question

(in cal)

tried everything but got nothing.

Answer 1

CoP=4.5
CoP=Qh/(Qh-Qc)=1/{1-(Qc/Qh)}=4.5
Qc/Qh=0.78

Qc=46.1 cal
Qh= Qc/0.78 = 46.1/0.78=59.1 cal

Answer 2

thanks :)