(a)
compressed 3 inches from its rest position
the amplitude is 3
(b)
returns to the same position after 0.8 seconds
the period is 0.8 seconds
If it had not been at its maximum compression when released, then things would have been a bit more complicated. But it only returns that far after a full period.
(c) frequency = 1/period
(d) cos(t) has its maximum at t=0. So, if y is the height of the end of the spring, which is hanging down, its maximum is when t=0. So,
y = cos(kt)
cos(kt) has period 2π/k. Since our period is 0.8 (or 4/5), we need 2π/k = 4/5. k=5π/2
y = cos(5π/2 t)
(e) now just plug in t=180 (3 minutes is 180 seconds)
A hanging spring is compressed 3 inches from its rest position and released at t = 0 seconds. It returns to the same position after 0.8 seconds.
I need help Finding:
a) the amplitude of the motion
b) the period of the motion
c) the frequency of the motion
d) a function that models the displacement, y, of the end of the spring from the rest position at time, t.
e) the displacement from the rest position at t= 3 min rounded to the tenths place
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