a hammervweighing 1kg moving with the speed of 10m/s strikes the head of the nail driving it 10cm into a wall. neglecting the mass of the nail calculate the acceleration during impact and the time interval during impact and the impulse

3 answers

change in momentum = 1 kg * 10 m/s
that is the impulse

average speed during stop = 5 m/s
distance = 5 m/s * t = .1 m
so
t = 0.5 seconds

a = change in speed/time 10/.5 = 20 m/s^2

this is easier to understand

ur right Kaira