A gymnist is swinging on a high bar. The distance between his waist and the bar is 1.1 m, as the drawing shows.

Question

At the top of the swing his speed is momentarily zero. ignoring friction and treating the gymnist as if all his mass is located at his waist, find his speed at the bottom of the swing.

Answer 1

I assume he is above the bar.

Change of height: 2.2 meters

so his KEnergy at the bottom will equal the change in PEnergy.
1/2 m v^2=mg(2.2)
mass divides out, solve for v

Answer 2

thanks bro