Ask a New Question

A gymnast on a high bar swings through two revolutions in a time of 1.90s. Find the angular velocity of the gymnast

1 answer

2 rev * 2 pi radians/rev = 4 pi radians
so
omega = 4 pi radians / 1.9 seconds

Ask a New Question or answer this question.

Similar Questions

A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3.00
1. 1 answer
A gymnast is swinging on a high bar. The distance between his waist and the bar is 1.26 m, as the drawing shows. At the top of
1. 0 answers
A gymnast is swinging on a high bar. The distance between his waist and the bar is 1.15 m, as the drawing shows. At the top of
1. 1 answer
A gymnast is swinging on a high bar. The distance between his waist and the bar is 1.1 m, as the drawing shows. At the top of
1. 1 answer

more similar questions