A gunman standing on a sloping ground fires up the slope. The initial speed of the bullet is v0= 340 m/s. The slope has an angle α= 12 degrees from the horizontal, and the gun points at an angle θ from the horizontal. The gravitational acceleration is g=10 m/s2.

Question

A gunman standing on a sloping ground fires up the slope. The initial speed of the bullet is v0= 340  m/s. The slope has an angle α= 12  degrees from the horizontal, and the gun points at an angle θ from the horizontal. The gravitational acceleration is g=10 m/s2.

(a) For what value of θ ( where θ>α) does the gun have a maximal range along the slope? (in degrees, from the horizontal)

θ=

unanswered
(b) What is the maximal range of the gun, lmax, along the slope? (in meters)

lmax=

Greco · Answer

a) 45+a/2=51 degrees b)(1−sin)*v0^2/(g*cos^2(á))

Anonimus · Answer

@Greco b one more time

Damon · Answer

Lordy me, and I did this one by mistake yesterday not knowing it was an 8:01 final question

Greco · Answer

(v_0^2*(1-sin(alpha))/(g*cos^2(alpha))