A gun is fired, and a 50gram bullet is accelerated to a muzzle speed of 100m/s. If the length of the gun barrel is 0.90m, what is the magnitude of the accelerating force? Assume the acceleration is constant.

Question

Help me please???

Answer 1

acceleration = change in velocity/change in time

magnitude of change in velocity = 100 m/s
(all in one direction)

time = distance/average speed = 0.9/50
= 1.8/100 = .018
so
a = 100/.018
then
F = m a = .050*100/.018 = 278 m/s^2
which is about 28 times gravity

Answer 2

v² = 2ax
100² = 2*0.9a
a =100² /1.8 = 5555.56
Force = ma = 0.05 x 5555.56 = 278 N

Answer 3

Thanks guys! I appreciate your help!

Answer 4

You are welcome. Now you have two ways to do it, both valid.

Answer 5

Welcome :)