force*distance=1/2 m v^2
solve for frictional force
a gun fires Aa bullet of mass 50g the bullet moving with a velocity of 100m/s strikes a sandbag get embedded after travelling 10cm calculate the resistance force exerted by the sand bag on the bulle
6 answers
100N
wrong ans
Is it 2500N ?
mass=50g=0.05kg
v=500
s=10cm=0.01m
K.E= 1/2mv^2
1/2x0.05x500x500
=6,250m/s^2
v=500
s=10cm=0.01m
K.E= 1/2mv^2
1/2x0.05x500x500
=6,250m/s^2
Using work energy theorem,
Wd = 1/2mv^2 - 1/2mu^2
Here, v is zero.
Mass is 0.05 kg And displacemt is 0.1 m.
Wd = -1/2 * 0.05 * 10000
Force * displacement = Wd
Thus, force can be calculated nd negative sign will indicate that it is resistant force
Wd = 1/2mv^2 - 1/2mu^2
Here, v is zero.
Mass is 0.05 kg And displacemt is 0.1 m.
Wd = -1/2 * 0.05 * 10000
Force * displacement = Wd
Thus, force can be calculated nd negative sign will indicate that it is resistant force