string equai6ton is where you start:
freq= sqrt (tension/ (mass/length) )
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2* length.
a. Assume tension/ mass/length is constant.
You changed lengfth by7 a factor of 9/8
fenw=fold * 1/(9/8)= fold*8/9, so it is lowered.
b. density changes by 2, which means mass/length changes by 2
fnew=fold sqrt(1/2)-.707*fold feq new is lower.
d. if diamenter is x2, then area is x4, so mass/length is x4.
A guitar string vibrates at 400 Hz and has a length of 0.8 m. Find the new frequency if
a. the string is lengthened to 0.9 m.
b. the string is replaced with another string, the density of which is greater by a factor of two.
c. The tension in the string is decreased by a factor of 0.4.
d. The string is replaced with another string, the diameter of which is twice as large.
1 answer
1 answer