Let n be the number of friends. The total cost for n friends to enter is 24n, and the total cost for parking and admissions is 18 + 24n.
We want to find the maximum number of friends, such that 18 + 24n ≤ 155.
Subtracting 18 from both sides, we get: 24n ≤ 137.
Dividing both sides by 24, we get: n ≤ 5.7.
The maximum number of friends who can go to the amusement park is 5 because you can't have a fraction of a person. Answer: \boxed{5}.
A group of friends wants to go to the amusement park. They have no more than $155 to spend on parking and admission. Parking is $18, and tickets cost $24 per person, including tax. What is the maximum number of people who can go to the amusement park?
5 answers
these are the answers I have A group of friends wants to go to the amusement park. They have no more than $560 to spend on parking and admission. Parking is $19.25, and tickets cost $19.75 per person, including tax. Which inequality can be used to determine xx, the maximum number of people who can go to the amusement park?
Answer
Multiple Choice Answers
560, is less than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≤19.75x+19.25
560, is less than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≤19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≥19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≥19.75x+19.25
Answer
Multiple Choice Answers
560, is less than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≤19.75x+19.25
560, is less than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≤19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≥19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≥19.75x+19.25
these are the answers that i have 560, is less than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≤19.75x+19.25
560, is less than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≤19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≥19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≥19.75x+19.25
560, is less than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≤19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, left bracket, x, plus, 19, point, 2, 5, right bracket560≥19.75(x+19.25)
560, is greater than or equal to, 19, point, 7, 5, x, plus, 19, point, 2, 5560≥19.75x+19.25
Select the values that make the inequality start fraction, p, divided by, minus, 4, end fraction, ≤, 2
−4
p
≤2 true. Then write an equivalent inequality, in terms of pp.
(Numbers written in order from least to greatest going across.)
−4
p
≤2 true. Then write an equivalent inequality, in terms of pp.
(Numbers written in order from least to greatest going across.)
I NEED HELP
1 answer