A ground state hydrogen atom absorbs a photon of light having a wavelength of 93.77 nm. It then gives off a photon having a wavelength of 1100 nm. What is the final state of the hydrogen atom

Answer 1

I would do this.
Use E = hc/wavelenth. Plug in 93.77 nm and solve for E in joules, then use
dE = 2.180E-18*(1/1 - 1/x^2) and solve for x. I think you will get 6. That is where the electron has been lifted; i.e., to n = 6.

Then E = hc/wavelength and substitute 1100; solve for E. Substitute E into
dE = 2.180E-18*(1/x^2 - 1/36) and solve for x. I think that will be n = 3. That's the final state.