A GREAT PYRAMID HAS A SQUARE BASE 230M ON EACH SIDE. THE 4 TRIANGULAR FACES EACH MAKE AN ANGLE OF 51.50' WITH THE GROUND.

1) HOW TALL IS THE PYRAMID ?

2) WHAT ARE THE DIMENSIONS OF EACH OF THESE TRIANGULAR FACES ?

1 answer

the center of the pyramid is 115m from each edge. Find the height h using

h/115 = tan51°50'

Now figure the slant height s, using

s^2 = 115^2+h^2

The isosceles triangles thus have base 230 and altitude s.

The edges of the pyramid(the equal sides of the triangles) have length x, where

x^2 = s^2+115^2