To determine which set of points could lie on a line with a slope of 5/3, we can calculate the slope using the formula:
slope = (change in y)/(change in x)
Let's calculate the slope for each set of points:
1) (15, 16) and (0, 4)
Change in y = 16 - 4 = 12
Change in x = 15 - 0 = 15
Slope = 12/15 = 4/5
2) (3, 9) and (6, 14)
Change in y = 14 - 9 = 5
Change in x = 6 - 3 = 3
Slope = 5/3
3) (0, 4) and (19, 9)
Change in y = 9 - 4 = 5
Change in x = 19 - 0 = 19
Slope = 5/19
4) (5, 7) and (10, 10)
Change in y = 10 - 7 = 3
Change in x = 10 - 5 = 5
Slope = 3/5
So, out of the four sets of points, the line with a slope of 5/3 could contain the points (3, 9) and (6, 14).
A graphed line has a slope of 5/3
. Which of the following points could the line contain?
Question 2 options:
(15, 16) and (0, 4)
(3, 9) and (6, 14)
(0, 4) and (19, 9)
(5, 7) and (10, 10)
1 answer