To derive the equation of the line in slope-intercept form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept, we can follow these steps:
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Identify the coordinates of the points:
- Point 1: \((0, -2)\)
- Point 2: \((1, 3)\)
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Calculate the slope (m): The slope \(m\) is calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting the coordinates of the points: \[ m = \frac{3 - (-2)}{1 - 0} = \frac{3 + 2}{1} = \frac{5}{1} = 5 \]
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Find the y-intercept (b): Since we have the y-intercept directly from point \((0, -2)\), we know that \(b = -2\).
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Write the equation: Now we can substitute \(m\) and \(b\) into the slope-intercept form: \[ y = 5x - 2 \]
Therefore, the equation of the line in slope-intercept form is: \[ y = 5x - 2 \]